How do you solve the equation #log_3 5+log_3 x=log_3 10#?

1 Answer
Noah G
Nov 20, 2016

#log_3 5 + log_3 x = log_3 10#

#log_3 x= log_3 10 - log_3 5#

Use the subtraction rule of logarithms: #log_a n - log_a m = log_a(n/m)#.

#log_3 x = log_ 3 (10/5)#

#log_3 x = log_3 2#

If #loga = logb#, then #a = b#.

#x = 2#

Hopefully this helps!

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