How do you solve #5y - 11= - 51#?

2 Answers
Nov 21, 2016

#y=-8#

Explanation:

Leave the 5y where it is and move numeric terms to the right side of the equation.

add 11 to both sides.

#5ycancel(-11)cancel(+11)=-51+11#

#rArr5y=-40#

To solve for y, divide both sides by 5

#(cancel(5) y)/cancel(5)=(-40)/5#

#rArry=-8" is the solution"#

Nov 21, 2016

#y=-8#.

Explanation:

By simple equation solving which is in factorisation of algebra.
#5y-11=-51# is a linear equation and it can be solved as follows:
#5y-11=-51#
#=>5y=-51+11#
#=>5y=-40#
#=>y=-40/5#
#=>y=-8#
#:.'y'# value is # -8#.