Question

How do you find the sum of the series `i/(i-1)` from i=2 to 6?

Answer 1

`sum_(i=2)^6 i/(i-1) = 437/60`

Explanation:

As there are only a few terms we could just write them out and compute the sum;
`sum_(i=2)^6 i/(i-1) = 2/(2-1) + 3/(3-1) + 4/(4-1) + 5/(5-1) + 6/(6-1)`
`:. sum_(i=2)^6 i/(i-1) = 2/1 + 3/2 + 4/3 + 5/4 + 6/5`
`:. sum_(i=2)^6 i/(i-1) = 437/60`