Question #7c1c3
1 Answer
Nov 22, 2016
Explanation:
Using the
#color(blue)"law of logarithms"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(log_b x=nhArrx=b^n)color(white)(2/2)|)))#
#"For" log_3 12=y#
#rArr12=3^y#