How do you solve #2- ( 7r + 4) = 33- 2r#?

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Answer 1 · 2016-11-23T13:14:59

#r = -7#

Step 1) Simplify the term within parenthesis:

#2 - 7r - 4 = 33 - 2r#

Step 2) Combine like terms on the left side of the equation:

#-7r - 2 = 33 - 2r#

Step 3) Solve for #r# while keeping the equation balanced:

#-7r - 2 + 2 + 2r = 33 - 2r + 2 + 2r#

-5r = 35#

#(-5r)/(-5) = 35/-5#

#r = -7#