Question

How do you integrate `int 1/x^4dx`?

Answer 1

`-1/(3x^3)+C`

Explanation:

We will have to know the rule `intx^ndx=x^(n+1)/(n+1)+C`, where `n!=-1`.

Rewriting the integral gives `int1/x^4dx=intx^-4dx`

Now using the rule: `intx^-4dx=x^(-4+1)/(-4+1)=x^-3/(-3)=-1/(3x^3)+C`