How do you write the equation of the circle with radius 4 and center at (0, 0)?

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Answer 1 · 2016-11-24T08:56:32

#x^2+y^2=16#

standard eqn. of circle with centre#" "(a,b)," "# radius #" "r#

#(x-a)^2+(y-b)^2=r^2#

In this case

#r=4," "(a,b)=(0,0)#

we have

#(x-0)^2+(y-0)^2=4^2#

giving

#x^2+y^2=16#