How do you integrate ln(2x)ln(2x)?
1 Answer
Nov 24, 2016
Explanation:
I=intln(2x)dxI=∫ln(2x)dx
We should use integration by parts in the absence of all other possible integration strategies. Integration by parts takes the form
{(u=ln(2x),=>,du=2/(2x)=1/x),(dv=dx,=>,v=x):}
Thus:
I=uv-intvdu=xln(2x)-intx1/xdx
I=xln(2x)-intdx
I=xln(2x)-x
I=x(ln(2x)-1)+C