Question

If `f(x)=2x^2+5sqrt(x+2)` how do you find f(0)?

Answer 1

`f(0)=+-5sqrt2`

Explanation:

For `f(0)`, simply substitute `x=0` into the function.

And thus, `f(0)=2(0)^2++-5sqrt(0+2)=+-5sqrt2`