How do you find #\int \frac { ( 2x ^ { 2} + 3) } { x ^ { 2} } d x#?

1 Answer
Steve M
Nov 25, 2016

# int (2x^2+3)/x^2dx = 2x-3/x+ c #

Explanation:

# int (2x^2+3)/x^2dx = int (2x^2)/x^2+3/x^2dx #
# :. int (2x^2+3)/x^2dx = int 2+3/x^2dx #
# :. int (2x^2+3)/x^2dx = int 2+3x^-2dx #
# :. int (2x^2+3)/x^2dx = 2x+3x^-1/-1 + c #
# :. int (2x^2+3)/x^2dx = 2x-3/x+ c #

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