How do you solve #|x - 15| + 4> 18#?

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Answer 1 · 2016-11-26T13:25:27

#x<1 or x>29#

First, you can subtract the term +4, to have:

#|x-15|>14#

and then, since the inequality

#|f(x)|>n#

is equivalent to

#f(x)<-n or f(x)>n#,

the given inequality becomes:

#x-15<-14 or x-15>14#

that's

#x<1 or x>29#