A #9.7"kg"# mass is positioned on top of a vertical spring. What is the upward force exerted on the mass by the spring?

2 Answers
Nov 20, 2016

#F_(sp)=85N#

Explanation:

Use Newton's second law, which (in summary) states that #F=ma#. Assuming no friction and that the mass is given in kilograms,

#F_(sp)=9.7kg*8.8m/s^2#

#F_(sp)=85N#

Nov 27, 2016

Net downward force on the 9.7 kg mass #F_n= 9.7xx8.8N#

Gravitational force on the 9.7 kg mass #F_g= 9.7xx9.8N#

If the upward force exerted by spring be #F_s# then

#F_n=F_g-F_s#

#=>F_s=F_g-F_n=9.7xx9.8-9.7xx8.8=9.7N#