How do you solve #5x+10=45#?

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Answer 1 · 2016-11-27T15:17:51

#x = 7#

First, subtract #10# from each side of the equation to isolate the #x# term and to keep the equation balanced:

#5x + 10 - 10 = 45 - 10#

#5x + 0 = 35#

#5x = 35#

Now, divide each side of the equation by #5# to solve for #x# while keeping the equation balanced:

#(5x)/5 = 35/5#

#(cancel(5)x)/cancel(5) = 7#

#x = 7#