Question #fc138

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Answer 1 · 2016-11-30T18:33:49

#k^3+3k^2-25k-75=(k+3)(k-5)(k+5)#

Factor by grouping first

#k^3+3k^2-25k-75=k^2(k+3)-25(k+3)#

factor out the common binomial factor #(k+3)#

#k^2(k+3)-25(k+3)=(k+3)(k^2-25)#

then factor the
difference of two squares #k^2-25=(k-5)(k+5)#

then continue

#(k+3)(k^2-25)=(k+3)(k-5)(k+5)#

the complete factored form is

#k^3+3k^2-25k-75=(k+3)(k-5)(k+5)#

God bless....I hope the explanation is useful.