Question

Question #de7ca

Answer 1

We know that the distance traveled by the body in *n th sec is given by the equation

`S_n=u+1/2a(2n-1)`

where u is the initial velocity and a is the uniform acceleration of the body.

In our given problem `u=0`

So distance traveled in 3rd sec

`S_3=1/2a(2*3-1)=5/2a`

And distance traveled in 4th sec

`S_4=1/2a(2*4-1)=7/2a`

So the ratio of distance traveled is

`S_3/S_4=5/7`