A bowling ball has a mass of 5.5 kg and a radius of 12 cm. It is released so that it rolls down alley at a rate of 12 rev/s. What's the magnitude if its angular momentum?

1 Answer
P dilip_k
Dec 3, 2016

Given
#M->"mass of the sphere"=5.5kg#
#R->"radius of the sphere"=12cm=0.12m#
#I->"moment of inertia of the sphere"#
#=2/5IR^2=2/5xx5.5xx(0.12)^2=0.03168kgm^2#
#omega-> "angular velocity"= 2pixx12=24pi" rad/s"#

#"Angular momentum"=Iomega=0.03168xx24pi~~2.39kgm^2s^-1#

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