How do you solve #abs(7-2x)-8<3#?

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Answer 1 · 2016-12-03T21:03:54

#-2< x <9#

The given inequality is equivalent to:

#|7-2x|<11#

and then

#-11<7-2x<11#

You can subtract 7 and get:

#-18<-2x<4#

Since you'll multiply by -1, the inequality will be flipped:

#-4<2x<18#

At the end you can divide all the terms by 2 and get:

#-2< x <9#