How do you solve #7x + 6< 8- 3x#?

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Answer 1 · 2016-12-04T04:06:15

see below

#7x+6\lt8-3x#
#10x+6\lt8\cancel(+3x-3x)#
#10x\cancel(+6-6)\lt2#
#x\lt2/10\rArrx\lt1/5\rArrx\lt0.2#

Answer 2 · 2016-12-04T04:46:50

#x<1/5#

Solve: #7x+6<8-3x#

Add #3x# to both sides.

#7x+3x+6<8#

#10x+6<8#

Subtract #6# from both sides.

#10x<2#

Divide both sides by #10#.

#x<2/10#

Simplify.

#x<1/5#