How do you solve #y= - 3+ x# and #y = - 3x + 1#?

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Answer 1 · 2016-12-04T15:17:02

#x=1# and #y=-2#

#y=-3+x#
#y=-3x+1#

From the first equation, we use the value of #y# as #color(red)((-3+x))# and substitute it for #y# in the second equation.

#y=-3x+1#

#color(red)(-3+x)=-3x+1#

Add #3# to both sides.

#x=-3x+4#

Add #3x# to both sides.

#4x=4#

Divide both sides by #4#.

#x=1#

In the first equation, substitute #x# with #1#.

#y=-3+1#

#y=-2#