Question

WeUsing the x-intercept and y-intercept, how do you graph `2x-3y=5`?

Answer 1

graph{2x-3y=5 [-10, 10, -5, 5]}

`equation: y=(2x-5)/3`

Explanation:

the equation can be converted into `y=mx+c`:

`2x - 3y = 5`

(-2x)

`-3y = -2x + 5`

(/3)

`-y= (-2x+5)/3`

(*-1)

`y= -(-2x+5)/3`

`y= (2x-5)/3`

Answer 2

`"Plot the points " (0,-5/3)" and " (5/2,0)`

Explanation:

When the line with given equation crosses the y-axis the corresponding x-coordinate at this point will be zero.
Substituting x = 0 into the equation gives the y-intercept.

`(2xx0)-3y=5rArr-3y=5rArry=-5/3`

`rArr(0,-5/3)" is the point on the y-axis"`

Similarly when the line crosses the x-axis the corresponding
y-coordinate at this point will be zero. Substituting y = 0 into the equation gives the x-intercept.

`2x-(3xx0)=5rArr2x=5rArrx=5/2`

`rArr(5/2,0)" is the point on the x-axis"`

Plot these 2 points and draw a straight line through them.
graph{2/3x-5/3 [-10, 10, -5, 5]}