How do you solve #\frac { 4} { 6} = \frac { 8} { x - 1}#?

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Answer 1 · 2016-12-04T21:36:48

#x = 13#

If you have just one fraction or term on each side of an equation,you can get rid of the fractions by cross-multiplying..

#4/6 = 8/(x-1)#

#4(x-1) = 6xx8#

#4x-4 = 48#

#4x = 48+4#

#4x = 52#

#x = 13#

Check: #8/(13-1) = 8/12#

Both #4/6 and 8/12# simplify to #2/3#