If a polynomial function f(x) has roots 3+sqrt5 and -6, what must be a factor of f(x)?

1 Answer
Dec 5, 2016

(x-3-sqrt5) and (x+6)

Explanation:

The factors is in the form of (x+z)

z+x must be equal to zero

Where x is the zeros (roots)

x=3+sqrt5 and -6

z+(3+sqrt5)=0
z=-3-sqrt5

(x-3-sqrt5) is the first factor

z+ -6=0
z=6

(x+6) is the second factor