How do you evaluate $2 i (- 6 + 3 i)$ $2i ( - 6+ 3i )$ ?

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How do you evaluate $2 i (- 6 + 3 i)$ $2i ( - 6+ 3i )$ ?

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Answer 1 · 2016-12-07T03:48:19

$- 6 - 12 i$ $-6-12i$

Explanation:

By multiplication
$2 i (- 6 + 3 i) = - 12 i + 6 i^{2}$ $2i(-6+3i)=-12i+6i^2$
where $i^{2} = - 1$ $i^2=-1$
Therefore
$- 12 i + 6 i^{2} = - 12 i - 6$ $-12i+6i^2=-12i-6$
It can be written as
$- 6 - 12 i$ $-6-12i$

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How do you evaluate $2 i (- 6 + 3 i)$ $2i ( - 6+ 3i )$ ?

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