How do you evaluate $2i ( - 6+ 3i )$ ?

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Answer 1 · 2016-12-07T03:48:19

$-6-12i$

By multiplication
$2i(-6+3i)=-12i+6i^2$
where $i^2=-1$
Therefore
$-12i+6i^2=-12i-6$
It can be written as
$-6-12i$

How do you evaluate 2i ( - 6+ 3i )2i ( - 6+ 3i )?