How do you write #21x^2+5x-35=3x^2-4x# in standard form?

1 Answer
smendyka
Dec 7, 2016

#18x^2 + 9x - 35 = 0#

Explanation:

To get to standard form you must all of the terms must be on one side of the equation and the quadratic must be equal to #0#:

#21x^2 + 5x - 35 - 3x^2 + 4x = 3x^2 - 4x - 3x^2 + 4x#

#21x^2 - 3x^2 + 5x + 4x - 35 = 3x^2 - 3x^2 - 4x + 4x#

#(21 - 3)x^2 + (5 + 4)x - 35 = 0 - 0#

#18x^2 + 9x - 35 = 0#

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