Length of a rectangle exceeds its width by #12# inches and its area is #768# square inches. Write the equation which solves this problem?

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Answer 1 · 2016-12-07T08:24:46

The desired quadratic equation is #w^2+12w-768=0#

Let the width of the rectangular window be #w# inches.

As length exceeds width by #12# inches, it s #w+12# inches.

Hence area is #w(w+12)# and as it is #768# square inches, we have

#w(w+12)=768#

or #w^2+12w=768#

or #w^2+12w-768=0#