Three numbers whose sum is #54# are such that one is double another and triple the other. What are the three numbers?

2 Answers
Dec 8, 2016

9, 18, 27

Explanation:

Let the unknown numbers be a, b, c where #a < b < c#

The question is not explicit enough to have no doubt about all the relationships.

No doubt about this one: #" "a+b+c=54#

Assumption

#b=2a#
#c=3a#

#a" "+" "b" "+" "c" "=54#
#darr" "darr" "darr#
#a" "2a" "3a" "=54#

#=> 6a=54#

Divide both sides by 6

#6/6a=54/6=9#

#color(blue)(a" "=" "color(white)(2)9)#
#color(blue)(b=2a=" "18)#
#ul(color(blue)(c=3a=" "27) larr" add"#
#" "54#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Suppose you meant

#b=2a#
#c=3b = 3(2a)=6a#

Then proceed using the same approach as the solution above.

Dec 8, 2016

#324/11#, #162/11#, #108/11#

Explanation:

I suspect that the question is incorrectly posed. For example, if two of the numbers were respectively double and triple the other number, then the numbers would be #9, 18, 27#.

With the question as posed, the three numbers take the form:

#x#, #x/2# and #x/3# for some constant #x# to be determined.

So their sum is:

#x+x/2+x/3 = (6x+3x+2x)/6 = (11x)/6 = 54#

Hence:

#x = (6*54)/11 = 324/11#

and the three numbers are:

#324/11#, #162/11#, #108/11#