Question

How do you solve `sin2x=-1`?

Answer 1

`(3pi)/4 + kpi`

Explanation:

Use trig unit circle -->
sin 2x = - 1 -->
`2x = (3pi)/2 + 2kpi`
`x = (3pi)/4 + kpi`

Answer 2

`(3pi)/4 + kpi`

Explanation:

Use trig unit circle -->
sin 2x = - 1 -->
`2x = (3pi)/2 + 2kpi`
`x = (3pi)/4 + kpi`