How do you factor #12x^{2}-14x+4=0#?

1 Answer
smendyka
Dec 10, 2016

#(6x - 4)(2x - 1) = 0#

Explanation:

We need to play with factors of 12 (1x12, 2x6, 3x4, 4x3, 6x2, 12x1) and factors of 4(1x4, 2x2, 4x1) to find the correct factors for adding up to #-14# in the #-14x# term:

#(6x - 4)(2x - 1) = 0#

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