Question

Question #0857c

Answer 1

`1`

Explanation:

To evaluate `2x-5` at `x=3`, we replace every instance of `x` in the given expression with a `3`.

`2color(red)(x)-5 -> 2color(red)((3))-5`

Then we evaluate the new expression.

`2(3)-5 = 6-5 = 1`