Let #f(x)=x^2(x^2-1)(x^2-2)(x^2-3)...(x^2-n)# What is the value of #f'(1)#?
Answer choices:
#f'(1)=2(n-1)!#
#f'(1)=(-1)^(n-1)*2(n-1)!#
#f'(1)=(-1)^(n)*(2n)!#
#f'(1)=(-1)^(n-1)*(2n-2)!#
None of the above
Answer choices:
None of the above
1 Answer
Dec 10, 2016
Explanation:
Finally