If #7/3 L# of a gas at room temperature exerts a pressure of #24 kPa# on its container, what pressure will the gas exert if the container's volume changes to #19/4 L#?

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Answer 1 · 2016-12-11T07:51:50

The pressure is #=11.8 kPa#

We use Boyle's Law

#P_1V_1=P_2V_2#

Here,

#P_1=24 kPa#

#V_1=7/3L#

#V_2=19/4L#

#P_2=(P_1V_1)/V_2=24*7/3*4/19=11.8kPa#