Question

How do you find the x- and y-intercepts of `y=-7x-3`?

Answer 1

The x- and y-intercepts are (0, -3) and (`-3/7`, 0)

Explanation:

The `y`-intercept is where `x = 0`. Substituting `0` for `x` in the equation and solving for `y` gives:

`y = (-7 xx 0) - 3`

`y = 0 - 3`

#y = -3

So, the y-intercept with x = 0 and y = -3 is: (0, -3)

The `x`-intercept is where `y = 0`. Substituting `0` for `y` in the equation and solving for `x` gives:

`0 = -7x - 3`

`0 + 3 = -7x - 3 + 3`

`3 = -7x - 0`

`3 = -7x`

`3/-7 = (-7x)/-7`

`-3/7 = (cancel(-7)x)/cancel(-7)`

`x = -3/7`

So, the x-intercept with y = 0 and x = -3/7 is: (`-3/7`, 0)