How do you find the discriminant of #4x^2 +12x+9=0#?

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Answer 1 · 2016-12-13T08:31:58

See explanation.

For a quadratic equation #ax^2+bx+c=0# the discriminant is defined as:

#Delta=b^2-4ac # ##

In the given equation we have:

#a=4#, #b=12# and #c=9#, so:

#Delta=12^2-4*4*9=144-144=0#