How do you find 4 consecutive odd integers with a sum of 18?

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Answer 1 · 2016-12-15T15:25:03

Because #x# is not an integer there is no solution to this problem involving consecutive odd integers.

4 consecutive odd integers would be every other integer (3, 5, 7, etc.).

There for let's call the first integer #x#.

Then the other three integers would be: #x + 2#, #x + 4# and #x + 6#

Adding these four integers together gives:

#x + x + 2 + x + 4 + x + 6 = 18#

Combining like terms and then solving gives:

#4x + 12 = 18#

#4x + 12 - 12 = 18 - 12#

#4x = 6#

#(4x)/4 = 6/4#

#x = 3/2#

Because #x# is not an integer there is no solution to this problem involving consecutive odd integers.