Question

How do you graph `y=1+sqrt(x-3)`?

Answer 1

Graph is inserted. See the vertex (3, 1) at the `larr`end

Explanation:

graph{1+sqrt(x-3)2 [0, 10, -10, 10]}

The equation `(y-1)^2=x-1` representing the parabola of size a = 1/4

and with vertex V(3, 1) is the combined equation to the pair

`y-1=+-sqrt(x-3)`

representing two halves of the parabola.

Here,

As `sqrt(x-3)>=0, x >=3 and y >=1`.

The graph for the other half given by `y = 1-sqrt(x-3)` follows.

graph{1-sqrt(x-3) [0, 10, -10, 10]}