Question

How do you determine `csctheta` given `sintheta=2/5,0^circ<theta<90^circ`?

Answer 1

`csctheta=5/2`

Explanation:

As `sintheta` is positive and is `2/5`

`csctheta` being inverse of `sintheta` i.e. `csctheta=1/sintheta`

= `1/(2/5)=1xx5/2=5/2`

Note that all the trigonometric ratios in range `0^o < theta < 90^o` are positive, but this does not matter as if `sintheta` is positive, `csctheta=1/sintheta` too will have same sign i.e. it will be positive.