How do you evaluate #3.3\div 3#?

2 Answers
Dec 16, 2016

1.1

Explanation:

#3.3÷3#, this can be rewritten as,

#3.3/3 = (33 * .1)/3 = (3*11 * .1)/3#

Now we can solve:

#(cancel3*11 * .1)/cancel3 = (11*.1)/(1) = 11*.1 = 1.1#

Dec 16, 2016

#" either " 1.1" or " 3#

Explanation:

The answer will be dependant on what the expression means.

#"If you mean " 3xx3÷3#

Evaluating from left to right gives.

#3xx3÷3=9÷3=3#

#" If you mean " 3.3÷3=3.3/3#

divide numerator/denominator by 3

#3.3/3=1.1/1=1.1#