How do you graph the equation #-4x+2y=8#?

1 Answer

See below:

Explanation:

There are many ways to go about it. I'm going to show how to do it by transforming the equation into a slope-intercept form.

First, we need to solve for #y#:

#-4x+2y=8#

#2y=4x+8#

#y=2x+4#

This equation is now in slope-intercept form, which has the general form of:

#y=mx+b#, where #m# is the slope and #b# is the y intercept.

We can first find the first point, the y-intercept, as #(0,4)# - that is, when #x=0, y=4#.

Next to do is work with the slope. In this case, #m=2#. Slope can be written as #"rise"/"run"# - and so a slope of 2 means the next point to find will be up 2 and to the right 1 of our y-intercept. This puts it at #(1,6)#. Connect those two points with a straightedge. It should look like this:

graph{2x+4 [-10, 10, -7, 7]}