How do you solve #k- 8- 3= - 6( k + 6) - ( - 5k + 5)#?

Question

479 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-17T14:58:29

#k = -15#

First, expand the terms in parenthesis and group and combine like terms on each side of the equation:

#k+ (-8 - 3) = -6k - 36 + 5k - 5#

#k - 11 = -6x + 5k - 36 - 5#

#k - 11 = (-6 + 5)k - 41#

#k - 11 = -1k - 41#

Now, we can isolate the #k# terms on one side of the equation and the constants on the other while keeping the equation balanced:

#k + k - 11 + 11 = -k + k - 41 + 11#

#2k - 0 = 0 - 30#

#2k = -30#

Now we can solve for #k# while keeping the equation balanced:

#(2k)/2 = (-30)/2#

#(cancel(2)k)/cancel(2) = -15#

#k = -15#