Question #d638b

1 Answer
Dec 18, 2016

The photon has a wavelength of # 5.56xx10^12 m#

Explanation:

To answer this question, we can use the wave equation formula:

http://www.antonine-education.co.uk/Pages/Physics_1/Particles/PP03/particles_page_3.htm

Where #lamda# is the wavelength and it has units of meters. #c# is the speed of light and it has a value of #3.0xx10^8 m/s#. #f# represents the frequency and it has units of Hertz or reciprocal seconds (#1/s#).

We know the frequency, #f#, and the speed of light since that is a constant. All we have to do is plug in the known values and solve for #lambda#:

#lambda = (3.0xx10^8 m/cancel"s")/((5.4xx10^-5)/cancel"s")#

#lambda = 5.56xx10^12 m#