Question

Question #4a240

Answer 1

`V_2~=40*L`

Explanation:

`(P_1V_1)/T_1=(P_2V_2)/T_2`

All temperature is reported on the `"Absolute scale"`; for `"pressure"` we use the relationship `760` `mm` `Hg` `-=` `1*atm.`

`V_2=T_2/(P_2)xx(P_1V_1)/T_1=(256.8*K)/((385*mm*Hg)/(760*mm*Hg*atm^-1))xx1/(303.5*K)xx((731*mm*Hg)/(760*mm*Hg*atm^-1))xx26.5*L~=40*L`