Question

A gas is placed in a piston whose volume was `19.7*L` under a pressure of `0.95*atm`. If the volume were reduced to `22.5*L`, what resultant pressure would develop?

Answer 1

The pressure of the system is 0.83 atm

Explanation:

To find the final pressure of the system we can use Boyle's Law:

Based on the information you've given me, we know the following variables:

`P_1` = 0.95 atm
`V_1` = 19.7 L
`V_2` = 22.5 L
`P_2` = `x`

Since we don't know what `P_2` is, the equation has to be rearranged by dividing both sides by `V_2` to get `P_2` by itself:

`P_2 = (P_1xxV_1)/V_2`

Now, just plug the given values into the equation:

`P_2 = (0.95 atm xx19.7cancelL)/(22.5cancelL)`

`P_2` = 0.83 atm