Question

How do you evaluate `10^(4log_10 2)`?

Answer 1

`10^(4 log_10 2) = 16`

Explanation:

By definition of `log_10`, for any `t > 0` we have:

`10^(log_10 t) = t`

Also note that for any `a, b` we have:

`10^(ab) = (10^a)^b`

So:

`10^(4 log_10 2) = (10^(log_10 2))^4 = 2^4 = 16`