How do you find #\sqrt { 98x ^ { 4} y ^ { 3} }#?

1 Answer
EZ as pi
Dec 20, 2016

#=7x^2ysqrt(2y)#

Explanation:

Write the number as the product of prime factors and the indices as even numbers where possible.

#sqrt(98x^4y^3) = sqrt(2xx7xx7 xxx^4 xx y^2 xxy)#

Find the square roots where possible and the other factors stay under the root.

#=7x^2ysqrt(2y)#

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