Question #97470

1 Answer
Dec 21, 2016

It is clear that the slab of steel at #70^@C# will loose heat via all three modes: Conduction, Convection and Radiation simultaneously and finally will be at ambient temperature given as #10^@C#.

#"Total heat lost by the steel slab"=mst#
where #m# is mass of slab, #s# specific heat of steel and #t# is change in its temperature.

Assuming density #rho# of steel#=7850kgm^-3#, #s=511Jkg^-1K^-1#
#m=rhoxx"volume"#
#m=7850xx(0.01xx1xx3)=235.5kg#

#:."Total heat lost by the steel slab"=235.5xx511xx(70-10)=7220430J#
-.-.-.-.-.-.-.-.-.-.-.-.-.-.

A. Now, rate of heat loss due to conduction #dotQ# from slab to deck is calculated as below.

Lets assume that the #1.0 cm# thick slab is lying flat on the deck.

Deck is at temperature of surroundings#=10^@C#

The heat loss from top to bottom of slab is found by taking
#ΔT = 70^@C – 10^@C = 60^@C = 60 K#, the temperature difference between the slab and deck.

Area #A# through which heat is lost#=1xx3=3m^2#

Thermal conductivity #k("steel") = 50Wm^-1K^-1#

We know that basic conduction problem equation is

#dot Q=(kAΔT)/"thickness of slab"#

Inserting above values we get
#dot Q=(50xx3xx60)/0.01#
#=>dot Q=900000W#

B. Similarly basic convection problem equation is
basic equation for convection,

#dotQ=hAΔT#
where heat transfer coefficient #h=10Wm^-2K^-1#.

Area #A# in contact with air#=2xx0.01(3+1)+3xx1=3.08m^2#

Inserting above values we get
#dotQ=10xx3.08xx60=1848W#

C. For radiation loss we have Stefan-Boltzmann Law.

#dotQ=εAσ(T_1^4– T_2^4)#
where #sigma# is the Stefan Boltzmann constant #= 5.670367 xx 10^-8 Wm^-2 K^-4#, #T_1K# is temperature of radiating body and #T_2K# is temperature of surroundings.

We are given the emissivity for steel, #ε= 0.85#. The radiating surface area as calculated above, #A= 3.08 m^2#
Inserting given values we get
#dotQ=0.85xx3.08xx5.670367 xx 10^-8(343^4– 283^4)=1102W#

D. Total heat loss rate #=900000+1848+1102=902950W#

Assuming rate of heat loss via each mode is constant throughout the time of loss.
Heat lost via conduction#=7220430xx900000/902950approx7196840J#