Question

How do you write `2x - 5y = 10` in slope intercept form?

Answer 1

`y=-2+2/5x`

Explanation:

Given -

`2x-5y=10`

Solve it for `y`
Add `-2x` to both sides

`2x-2x-5y=10-2x`
`cancel(2x)cancel(-2x)-5y=10-2x`

Divide both sides by `-5`

`(-5y)/(-5)=(10-2x)/(-5)`

`(cancel(-5)y)/cancel(-5)=(10-2x)/(-5)`
`y=(10-2x)/(-5)`
`y=10/(-5)-(2x)/(-5)`
`y=-2+2/5x`