Question

Question #8a714

Answer 1

`pH=12`

Explanation:

`[HO^-]=(4*g)/(39.99*g*mol^-1)xx1/(10*L)=0.01*mol*L^-1`.

Now `pOH=-log_10[HO^-]=-log_10(0.01)=2.0`

But `pH+pOH=14`, and thus `pH=12`

That `pH+pOH=14` is key, and of course it stems from the autoprotolysis equilibrium, `[HO^-][H_3O^+]=10^-14`.