How do you convert #y=2x-1# to polar form?

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Answer 1 · 2016-12-22T09:07:21

#r=1/(2costheta-sintheta)#

for polars

#r^2=x^2+y^2#

#x=rcostheta#

#y=rsintheta#

#y=2x-1#

#rsintheta=2rcostheta-1#

#=>2rcostheta-rsintheta=1#

#r(2costheta-sintheta)=1#

#r=1/(2costheta-sintheta)#