Question #2beda

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Answer 1 · 2016-12-23T13:18:32

Relative atomic masses of

#N->14#

#O->16#

Relative molecular masses of

#NO_2->14+2*16=46#

#N_2O_4->2*14+4*16=92#
Since #"vapour density" =1/2"molecular mass"#

Vapour densities of

#NO_2->=46/2=23#

#N_2O_4->(2*14+4*16)/2=92/2=46#

Let x be the number of moles of #NO_2# in 100 moles mixture.

So the vapour density of the mixture will be

#(23*x+46*(100-x))/100=38.3#

#=>23x+4600-46x=3830#

#=>23x=770#

#=>x=770/23~~33.48#