If 17/6 L of a gas at room temperature exerts a pressure of 24 kPa on its container, what pressure will the gas exert if the container's volume changes to 5/4 L?

1 Answer
Dec 25, 2016

54.4kPa

Explanation:

We can obtain the final pressure via Boyle's Law:

http://slideplayer.com/slide/698879/http://slideplayer.com/slide/698879/

Let's identify the known and unknown variables:

color(blue)("Knowns:")
- Initial Volume
- Final Volume
- Initial Pressure

color(magenta)("Unknowns:")
- Final Pressure

All we have to do is rearrange the equation to solve for the final pressure. We do this by dividing both sides by V_2 in order to get P_2 by itself like this:
P_2=(P_1xxV_1)/V_2

Now all we do is plug in the values and we're done!

P_2= (24kPa xx 17/6cancel"L")/(5/4\cancel"L") = 54.4 kPa